Class 10 Maths Notes — Chapter 13: Statistics
Mean, median, and mode of grouped data.
Detailed NCERT notes
- For grouped frequency distributions, class marks xᵢ = (upper + lower)/2 represent each class.
- Direct method for mean: x̄ = Σfᵢxᵢ / Σfᵢ.
- Assumed mean method: choose a (usually a middle xᵢ); compute dᵢ = xᵢ − a; then x̄ = a + Σfᵢdᵢ / Σfᵢ.
- Step-deviation method: choose class width h; uᵢ = (xᵢ − a)/h; x̄ = a + h · Σfᵢuᵢ / Σfᵢ.
- Median formula: Median = l + [(n/2 − cf)/f] × h, where l = lower boundary of median class, n = Σfᵢ, cf = cumulative frequency before median class, f = frequency of median class, h = class width.
- Median class = the class in which the cumulative frequency first reaches or exceeds n/2.
- Mode formula: Mode = l + [(f₁ − f₀)/(2f₁ − f₀ − f₂)] × h, where f₁ = frequency of modal class, f₀ = previous, f₂ = next.
- Modal class = class with the highest frequency.
- Empirical relation: 3 Median = Mode + 2 Mean (approximate).
- For continuous data, ensure classes are 'exclusive' (like 10–20, 20–30) or convert 'inclusive' classes (like 10–19, 20–29) by adjusting boundaries.
- Note: ogive/less-than and more-than curves were rationalised; focus on the three central-tendency formulas.
Formulas & key results
- Mean (direct): x̄ = Σfᵢxᵢ / Σfᵢ
- Mean (assumed): x̄ = a + Σfᵢdᵢ / Σfᵢ
- Mean (step-deviation): x̄ = a + h · Σfᵢuᵢ / Σfᵢ
- Median = l + [(n/2 − cf)/f] × h
- Mode = l + [(f₁ − f₀)/(2f₁ − f₀ − f₂)] × h
- Empirical: 3 Median = Mode + 2 Mean
Mind map
- Grouped data → class marks
- Mean via 3 methods
- Median: locate class via cumulative frequency
- Mode: locate modal class
- Empirical relation among mean, median, mode
Tricks & shortcuts
- Step-deviation method is fastest when class widths are equal.
- Locate median class by scanning cumulative frequency for n/2.
- If distribution is nearly symmetric, mean ≈ median ≈ mode.
Common mistakes to avoid
- Wrong cf class for median (must be BEFORE median class).
- Confusing f₀, f₁, f₂ in mode formula.
- Using inclusive classes without adjusting to continuous form.
Competency-based questions & answers
- Q. Modal class of frequencies 10, 15, 25, 20, 18 is which?A. Highest frequency = 25 ⇒ 3rd class is the modal class.
- Q. For a symmetric distribution, mean = 30. What is the median?A. Approximately 30 (since 3M = Mode + 2·Mean and mode ≈ mean ⇒ M ≈ mean).