Class 10 Maths Notes — Chapter 14: Probability
Classical (theoretical) probability of equally likely outcomes.
Detailed NCERT notes
- Random experiment: outcome cannot be predicted with certainty.
- Sample space S = set of all possible outcomes; event E ⊆ S.
- For equally likely outcomes: P(E) = number of favourable outcomes / total number of outcomes.
- 0 ≤ P(E) ≤ 1 for every event E. P(impossible) = 0, P(sure) = 1.
- Complementary events: P(E) + P(not E) = 1, i.e. P(Ē) = 1 − P(E).
- For a coin toss: S = {H, T}, 2 outcomes. Two coins: 4 outcomes. n coins: 2ⁿ outcomes.
- For a die (6 faces): S = {1, 2, 3, 4, 5, 6}. Two dice: 36 outcomes (ordered pairs).
- For a standard deck of 52 cards: 4 suits (spades, hearts, diamonds, clubs), each with 13 cards. Face cards = J, Q, K (12 total); Aces = 4; red cards = 26; black = 26.
- Card-drawing 'without replacement' vs 'with replacement' matters — although at Class 10 level, single-draw is the usual setup.
- For 'at least' questions, complement is often easier: P(at least one) = 1 − P(none).
- Always write the total outcomes and favourable outcomes explicitly for full marks.
Formulas & key results
- P(E) = favourable outcomes / total outcomes
- 0 ≤ P(E) ≤ 1
- P(E) + P(not E) = 1
Mind map
- Sample space → event → equally likely
- Complementary events
- Coins, dice, cards contexts
Tricks & shortcuts
- List sample space explicitly for two-dice/coin problems.
- Use complement for 'at least one' style questions.
Common mistakes to avoid
- Assuming outcomes are equally likely without checking.
- Confusing 'at least' with 'exactly'.
- Forgetting there are 12 face cards (or 16 if aces counted).
Competency-based questions & answers
- Q. Two dice are thrown. Find P(sum = 8).A. Favourable: (2,6), (3,5), (4,4), (5,3), (6,2) → 5. P = 5/36.
- Q. One card is drawn from a well-shuffled deck. Find P(it is a red face card).A. Red face cards = 6 (J, Q, K of hearts and diamonds). P = 6/52 = 3/26.
- Q. A bag has 3 red, 5 black, 4 white balls. One is drawn. Find P(not red).A. Total = 12; not red = 9. P = 9/12 = 3/4.